4y^2+20y=11

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Solution for 4y^2+20y=11 equation:


Simplifying
4y2 + 20y = 11

Reorder the terms:
20y + 4y2 = 11

Solving
20y + 4y2 = 11

Solving for variable 'y'.

Reorder the terms:
-11 + 20y + 4y2 = 11 + -11

Combine like terms: 11 + -11 = 0
-11 + 20y + 4y2 = 0

Factor a trinomial.
(-11 + -2y)(1 + -2y) = 0

Subproblem 1

Set the factor '(-11 + -2y)' equal to zero and attempt to solve: Simplifying -11 + -2y = 0 Solving -11 + -2y = 0 Move all terms containing y to the left, all other terms to the right. Add '11' to each side of the equation. -11 + 11 + -2y = 0 + 11 Combine like terms: -11 + 11 = 0 0 + -2y = 0 + 11 -2y = 0 + 11 Combine like terms: 0 + 11 = 11 -2y = 11 Divide each side by '-2'. y = -5.5 Simplifying y = -5.5

Subproblem 2

Set the factor '(1 + -2y)' equal to zero and attempt to solve: Simplifying 1 + -2y = 0 Solving 1 + -2y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2y = 0 + -1 -2y = 0 + -1 Combine like terms: 0 + -1 = -1 -2y = -1 Divide each side by '-2'. y = 0.5 Simplifying y = 0.5

Solution

y = {-5.5, 0.5}

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